What are the solutions to the equation (a+1)^2=25 ?

The solutions to the equation (a+1)^2=25 are a=4,a=-6

Find the zeros of (a+1)^2=25

The zeros of (a+1)^2=25 are a=4,a=-6

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(a + 1)^{2} = 25

a = 4, a = - 6

Solution steps

(a + 1)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

a + 1 = 25 : a = 4

Solve

a + 1 = - 25 : a = - 6

The solutions to the quadratic equation are:

a = 4, a = - 6

2 < \frac{5 x - 8}{3} \leq 9

x^{3} + 7 x^{2} \geq 9 x + 63

a^{4} + 14 a^{2} + 49

2 (x + 5) = 3 (x - 1) + 17

x^{2} + 2 x - 63

What are the solutions to the equation (a+1)^2=25 ?
The solutions to the equation (a+1)^2=25 are a=4,a=-6
Find the zeros of (a+1)^2=25
The zeros of (a+1)^2=25 are a=4,a=-6