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Popular >

(x+4)(x^2-5x-14)>= 0

Solution

(x + 4) (x^{2} - 5 x - 14) \geq 0

Solution

- 4 \leq x \leq - 2 or x \geq 7

+1

Interval Notation

[- 4, - 2] \cup [7, \infty)

Solution steps

(x + 4) (x^{2} - 5 x - 14) \geq 0

Factor

(x + 4) (x^{2} - 5 x - 14) : (x + 4) (x + 2) (x - 7)

(x + 4) (x + 2) (x - 7) \geq 0

Identify the intervals

- 4 \leq x \leq - 2 or x \geq 7

Popular Examples

(x - 7)^{2} (x + 8) > 0

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\frac{3}{4} - \frac{1}{16}

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factor 3x^3(x-2)+9x^2(x-2)^2 factor

3 x^{3} (x - 2) + 9 x^{2} (x - 2)^{2}

Frequently Asked Questions (FAQ)

What is (x+4)(x^2-5x-14)>= 0 ?
The solution to (x+4)(x^2-5x-14)>= 0 is -4<= x<=-2\lor x>= 7