What are the solutions to the equation x^2-2x-13=0 ?

The solutions to the equation x^2-2x-13=0 are x=1+sqrt(14),x=1-sqrt(14)

Find the zeros of x^2-2x-13=0

The zeros of x^2-2x-13=0 are x=1+sqrt(14),x=1-sqrt(14)

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x^{2} - 2 x - 13 = 0

x = 1 + 14, x = 1 - 14

Decimal Notation

x = 4.74165 \dots, x = - 2.74165 \dots

Solution steps

x^{2} - 2 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 13 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 13) = 214

x_{1, 2} = \frac{- ( - 2 ) \pm 2 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 14}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 14}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 14}{2 \cdot 1} : 1 + 14

x = \frac{- ( - 2 ) - 2 14}{2 \cdot 1} : 1 - 14

The solutions to the quadratic equation are:

x = 1 + 14, x = 1 - 14

\frac{1}{81} < 9^{2 x - 4}

∣ 2 - 3 x ∣ + 3 < 8

7 x - 35 < 2 (x - 5)

x - 2 = - 10

\frac{1}{3 x} > \frac{2}{x - 1}

What are the solutions to the equation x^2-2x-13=0 ?
The solutions to the equation x^2-2x-13=0 are x=1+sqrt(14),x=1-sqrt(14)
Find the zeros of x^2-2x-13=0
The zeros of x^2-2x-13=0 are x=1+sqrt(14),x=1-sqrt(14)