What are the solutions to the equation s^2+10s+1=0 ?

The solutions to the equation s^2+10s+1=0 are s=-5+2sqrt(6),s=-5-2sqrt(6)

Find the zeros of s^2+10s+1=0

The zeros of s^2+10s+1=0 are s=-5+2sqrt(6),s=-5-2sqrt(6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

s^{2} + 10 s + 1 = 0

s = - 5 + 26, s = - 5 - 26

Decimal Notation

s = - 0.10102 \dots, s = - 9.89897 \dots

Solution steps

s^{2} + 10 s + 1 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 1 = 46

s_{1, 2} = \frac{- 10 \pm 4 6}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 10 + 4 6}{2 \cdot 1}, s_{2} = \frac{- 10 - 4 6}{2 \cdot 1}

s = \frac{- 10 + 4 6}{2 \cdot 1} : - 5 + 26

s = \frac{- 10 - 4 6}{2 \cdot 1} : - 5 - 26

The solutions to the quadratic equation are:

s = - 5 + 26, s = - 5 - 26

∣ x ∣ = 12

\frac{1}{2} x + 8 = 10

x^{2} + 13 = 4 x

i^{123}

\frac{3}{4} + 7

What are the solutions to the equation s^2+10s+1=0 ?
The solutions to the equation s^2+10s+1=0 are s=-5+2sqrt(6),s=-5-2sqrt(6)
Find the zeros of s^2+10s+1=0
The zeros of s^2+10s+1=0 are s=-5+2sqrt(6),s=-5-2sqrt(6)