What is the answer to 2y+7-4(3-2y)=-8 ?

The answer to 2y+7-4(3-2y)=-8 is y=-3/10

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2y+7-4(3-2y)=-8

2 y + 7 - 4 (3 - 2 y) = - 8

y = - \frac{3}{10}

Decimal Notation

y = - 0.3

Solution steps

2 y + 7 - 4 (3 - 2 y) = - 8

Move

7

to the right side

2 y - 4 (3 - 2 y) = - 15

Expand

2 y - 4 (3 - 2 y) : 10 y - 12

10 y - 12 = - 15

Move

12

to the right side

10 y = - 3

Divide both sides by

10

y = - \frac{3}{10}

4 x^{2} - 12 x

15 x^{2} - 14 x - 8

10 b^{2} + 20 b + 30

(4)^{\frac{4}{3}}

x^{2} - 70 x + 200 = 0

What is the answer to 2y+7-4(3-2y)=-8 ?
The answer to 2y+7-4(3-2y)=-8 is y=-3/10
Solve for y: 2y+7-4(3-2y)=-8
The solution is y=-3/10