What are the solutions to the equation v^2+v-20=0 ?

The solutions to the equation v^2+v-20=0 are v=4,v=-5

Find the zeros of v^2+v-20=0

The zeros of v^2+v-20=0 are v=4,v=-5

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v^{2} + v - 20 = 0

v = 4, v = - 5

Solution steps

v^{2} + v - 20 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 20) = 9

v_{1, 2} = \frac{- 1 \pm 9}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 1 + 9}{2 \cdot 1}, v_{2} = \frac{- 1 - 9}{2 \cdot 1}

v = \frac{- 1 + 9}{2 \cdot 1} : 4

v = \frac{- 1 - 9}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

v = 4, v = - 5

4 < x

16 x^{2} = 24 x - 9

x^{2} + x + 2

(x - 5)^{2} (x - 1) (x + 3) < 0

4 x^{2} + 4 x y + y^{2}

What are the solutions to the equation v^2+v-20=0 ?
The solutions to the equation v^2+v-20=0 are v=4,v=-5
Find the zeros of v^2+v-20=0
The zeros of v^2+v-20=0 are v=4,v=-5