What are the solutions to the equation x^2-5x-36=0 ?

The solutions to the equation x^2-5x-36=0 are x=9,x=-4

Find the zeros of x^2-5x-36=0

The zeros of x^2-5x-36=0 are x=9,x=-4

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x^{2} - 5 x - 36 = 0

x = 9, x = - 4

Solution steps

x^{2} - 5 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 36) = 13

x_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 1}

x = \frac{- ( - 5 ) + 13}{2 \cdot 1} : 9

x = \frac{- ( - 5 ) - 13}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 9, x = - 4

3 + 5 e = 8 (6 - 7 e)

- x^{2} - 77 x + 78

\frac{m}{9} + \frac{2}{3} = \frac{7}{3}

2 x^{3} - 4 x^{2} - 34 x + 68

x^{4} - 7 x^{3} + 6 x^{2} + 19 x + 5

What are the solutions to the equation x^2-5x-36=0 ?
The solutions to the equation x^2-5x-36=0 are x=9,x=-4
Find the zeros of x^2-5x-36=0
The zeros of x^2-5x-36=0 are x=9,x=-4