What are the solutions to the equation 2x^2=x+15 ?

The solutions to the equation 2x^2=x+15 are x=3,x=-5/2

Find the zeros of 2x^2=x+15

The zeros of 2x^2=x+15 are x=3,x=-5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} = x + 15

x = 3, x = - \frac{5}{2}

Decimal Notation

x = 3, x = - 2.5

Solution steps

2 x^{2} = x + 15

Move

15

to the left side

2 x^{2} - 15 = x

Move

x

to the left side

2 x^{2} - 15 - x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 15) = 11

x_{1, 2} = \frac{- ( - 1 ) \pm 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 11}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 11}{2 \cdot 2}

x = \frac{- ( - 1 ) + 11}{2 \cdot 2} : 3

x = \frac{- ( - 1 ) - 11}{2 \cdot 2} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = 3, x = - \frac{5}{2}

3 y^{2} - 3 y - 90

\frac{( 2 \cdot 3 - 1 ) ( 2 \cdot 3 - 3 ) ( 2 \cdot 3 - 5 )}{2 ^{3}}

49 x^{2} - 144 y^{4}

18 - 50 w^{2}

6 n + 1 = 2 n - 7

What are the solutions to the equation 2x^2=x+15 ?
The solutions to the equation 2x^2=x+15 are x=3,x=-5/2
Find the zeros of 2x^2=x+15
The zeros of 2x^2=x+15 are x=3,x=-5/2