What are the solutions to the equation t^2-9t=-14 ?

The solutions to the equation t^2-9t=-14 are t=7,t=2

Find the zeros of t^2-9t=-14

The zeros of t^2-9t=-14 are t=7,t=2

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t^{2} - 9 t = - 14

t = 7, t = 2

Solution steps

t^{2} - 9 t = - 14

Move

14

to the left side

t^{2} - 9 t + 14 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 14 = 5

t_{1, 2} = \frac{- ( - 9 ) \pm 5}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 9 ) + 5}{2 \cdot 1}, t_{2} = \frac{- ( - 9 ) - 5}{2 \cdot 1}

t = \frac{- ( - 9 ) + 5}{2 \cdot 1} : 7

t = \frac{- ( - 9 ) - 5}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

t = 7, t = 2

(- 2 - 4 i) + (1 + 6 i)

(x + 2) (x - 3) \leq 0

16 n^{2} + 40 n + 25

x^{4} - 4 x^{3} + 4 x^{2}

x^{2} - 4 x - 12 \geq 0

What are the solutions to the equation t^2-9t=-14 ?
The solutions to the equation t^2-9t=-14 are t=7,t=2
Find the zeros of t^2-9t=-14
The zeros of t^2-9t=-14 are t=7,t=2