What are the solutions to the equation 12^2+x^2=20^2 ?

The solutions to the equation 12^2+x^2=20^2 are x=16,x=-16

Find the zeros of 12^2+x^2=20^2

The zeros of 12^2+x^2=20^2 are x=16,x=-16

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1 2^{2} + x^{2} = 2 0^{2}

x = 16, x = - 16

Solution steps

1 2^{2} + x^{2} = 2 0^{2}

Move

1 2^{2}

to the right side

x^{2} = 256

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 256, x = - 256

256 = 16

- 256 = - 16

x = 16, x = - 16

∣ 5 v - 5 ∣ < 15

2 π - \frac{π}{3}

5 i^{3}

f (x) = (e^{- \frac{x}{2}})^{2}

49 \times 2 - 9

What are the solutions to the equation 12^2+x^2=20^2 ?
The solutions to the equation 12^2+x^2=20^2 are x=16,x=-16
Find the zeros of 12^2+x^2=20^2
The zeros of 12^2+x^2=20^2 are x=16,x=-16