What are the solutions to the equation r^2+3r-10=0 ?

The solutions to the equation r^2+3r-10=0 are r=2,r=-5

Find the zeros of r^2+3r-10=0

The zeros of r^2+3r-10=0 are r=2,r=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r^{2} + 3 r - 10 = 0

r = 2, r = - 5

Solution steps

r^{2} + 3 r - 10 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 10) = 7

r_{1, 2} = \frac{- 3 \pm 7}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 3 + 7}{2 \cdot 1}, r_{2} = \frac{- 3 - 7}{2 \cdot 1}

r = \frac{- 3 + 7}{2 \cdot 1} : 2

r = \frac{- 3 - 7}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

r = 2, r = - 5

e^{\frac{2 πi}{2}}

256 - x^{8}

2 x^{2} - 128

x^{2} + 7 x - 8 \leq 0

x^{2} - 2 = x^{2} - x - 6

What are the solutions to the equation r^2+3r-10=0 ?
The solutions to the equation r^2+3r-10=0 are r=2,r=-5
Find the zeros of r^2+3r-10=0
The zeros of r^2+3r-10=0 are r=2,r=-5