What is 8-6| k/2 |>-10 ?

The solution to 8-6| k/2 |>-10 is -6<k<6

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8-6| k/2 |>-10

8 - 6 \frac{k}{2} > - 10

- 6 < k < 6

Interval Notation

(- 6, 6)

Solution steps

8 - 6 \frac{k}{2} > - 10

Move

8

to the right side

- 6 \frac{k}{2} > - 18

Multiply both sides by

- 1

6 \frac{k}{2} < 18

Divide both sides by

6

\frac{k}{2} < 3

Apply absolute rule: If

∣ u ∣ < a, a > 0

then

- a < u < a

- 3 < \frac{k}{2} < 3

\frac{k}{2} > - 3 and \frac{k}{2} < 3

k > - 6 and k < 6

Merge Overlapping Intervals

- 6 < k < 6

0. 7^{8 - x^{2}} > 0. 7^{2 x}

x > 7 - x

x^{2} - 3 x - 88 = 0

((2^{4})^{5})^{6}

7^{2} + 6^{2} = x^{2}