What are the solutions to the equation 4x^2-8x+7=0 ?

The solutions to the equation 4x^2-8x+7=0 are x=1+i(sqrt(3))/2 ,x=1-i(sqrt(3))/2

Find the zeros of 4x^2-8x+7=0

The zeros of 4x^2-8x+7=0 are x=1+i(sqrt(3))/2 ,x=1-i(sqrt(3))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} - 8 x + 7 = 0

x = 1 + i \frac{3}{2}, x = 1 - i \frac{3}{2}

Solution steps

4 x^{2} - 8 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 \cdot 7}{2 \cdot 4}

Simplify

(- 8)^{2} - 4 \cdot 4 \cdot 7 : 43 i

x_{1, 2} = \frac{- ( - 8 ) \pm 4 3 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 3 i}{2 \cdot 4}, x_{2} = \frac{- ( - 8 ) - 4 3 i}{2 \cdot 4}

x = \frac{- ( - 8 ) + 4 3 i}{2 \cdot 4} : 1 + i \frac{3}{2}

x = \frac{- ( - 8 ) - 4 3 i}{2 \cdot 4} : 1 - i \frac{3}{2}

The solutions to the quadratic equation are:

x = 1 + i \frac{3}{2}, x = 1 - i \frac{3}{2}

5 u \leq 8 u - 21

x - 9 \leq - 8

\frac{x}{5} + x = 180

- 13 x < 65

10 x^{2} - 5 x + 25

What are the solutions to the equation 4x^2-8x+7=0 ?
The solutions to the equation 4x^2-8x+7=0 are x=1+i(sqrt(3))/2 ,x=1-i(sqrt(3))/2
Find the zeros of 4x^2-8x+7=0
The zeros of 4x^2-8x+7=0 are x=1+i(sqrt(3))/2 ,x=1-i(sqrt(3))/2