What is the answer to (2x+1)/3+(x-5)/2 =4 ?

The answer to (2x+1)/3+(x-5)/2 =4 is x= 37/7

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(2x+1)/3+(x-5)/2 =4

\frac{2 x + 1}{3} + \frac{x - 5}{2} = 4

x = \frac{37}{7}

Decimal Notation

x = 5.28571 \dots

Solution steps

\frac{2 x + 1}{3} + \frac{x - 5}{2} = 4

Multiply by LCM

2 (2 x + 1) + 3 (x - 5) = 24

Expand

2 (2 x + 1) + 3 (x - 5) : 7 x - 13

7 x - 13 = 24

Move

13

to the right side

7 x = 37

Divide both sides by

7

x = \frac{37}{7}

- 5 x^{- 1}

8 x^{3} - 216

- 3 (y - 5) = 24

x^{2} - 1 < 0

\frac{4 + 3 i}{1 + 2 i}

What is the answer to (2x+1)/3+(x-5)/2 =4 ?
The answer to (2x+1)/3+(x-5)/2 =4 is x= 37/7
Solve for x: (2x+1)/3+(x-5)/2 =4
The solution is x= 37/7