What are the solutions to the equation b^2+25b=0 ?

The solutions to the equation b^2+25b=0 are b=0,b=-25

Find the zeros of b^2+25b=0

The zeros of b^2+25b=0 are b=0,b=-25

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b^{2} + 25 b = 0

b = 0, b = - 25

Solution steps

b^{2} + 25 b = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

2 5^{2} - 4 \cdot 1 \cdot 0 = 25

b_{1, 2} = \frac{- 25 \pm 25}{2 \cdot 1}

Separate the solutions

b_{1} = \frac{- 25 + 25}{2 \cdot 1}, b_{2} = \frac{- 25 - 25}{2 \cdot 1}

b = \frac{- 25 + 25}{2 \cdot 1} : 0

b = \frac{- 25 - 25}{2 \cdot 1} : - 25

The solutions to the quadratic equation are:

b = 0, b = - 25

3 - 10

a^{2} + 1 = 0

\frac{\frac{2}{5} + \frac{1}{2}}{\frac{1}{10} + \frac{3}{15}}

18 x^{2} - 50 y^{2}

18 - 3 u = - 24

What are the solutions to the equation b^2+25b=0 ?
The solutions to the equation b^2+25b=0 are b=0,b=-25
Find the zeros of b^2+25b=0
The zeros of b^2+25b=0 are b=0,b=-25