What are the solutions to the equation x^2-35=2x ?

The solutions to the equation x^2-35=2x are x=7,x=-5

Find the zeros of x^2-35=2x

The zeros of x^2-35=2x are x=7,x=-5

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x^{2} - 35 = 2 x

x = 7, x = - 5

Solution steps

x^{2} - 35 = 2 x

Move

2 x

to the left side

x^{2} - 35 - 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 2 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 35 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 35) = 12

x_{1, 2} = \frac{- ( - 2 ) \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 12}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 12}{2 \cdot 1}

x = \frac{- ( - 2 ) + 12}{2 \cdot 1} : 7

x = \frac{- ( - 2 ) - 12}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 7, x = - 5

x^{4} - 5 x^{3} - 5 x^{2} + 23 x + 10

y^{6} - 27 x^{6}

8 = - 2 n

36 - 9 x

2 x - 8 = 3 x - 10

What are the solutions to the equation x^2-35=2x ?
The solutions to the equation x^2-35=2x are x=7,x=-5
Find the zeros of x^2-35=2x
The zeros of x^2-35=2x are x=7,x=-5