What are the solutions to the equation 5(x^2-7)-8=-8 ?

The solutions to the equation 5(x^2-7)-8=-8 are x=sqrt(7),x=-sqrt(7)

Find the zeros of 5(x^2-7)-8=-8

The zeros of 5(x^2-7)-8=-8 are x=sqrt(7),x=-sqrt(7)

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5 (x^{2} - 7) - 8 = - 8

x = 7, x = - 7

Decimal Notation

x = 2.64575 \dots, x = - 2.64575 \dots

Solution steps

5 (x^{2} - 7) - 8 = - 8

Move

8

to the right side

5 (x^{2} - 7) = 0

Divide both sides by

5

x^{2} - 7 = 0

Move

7

to the right side

x^{2} = 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 7, x = - 7

\frac{\frac{\frac{7}{5}}{5}}{2}

x^{2} + x \leq 2

42 a + 16 x y^{3} - 48 y^{2} - 14 a x y

p^{2} - 11 p = 0

1 = b^{2} + (\frac{3 b}{2})^{2}

What are the solutions to the equation 5(x^2-7)-8=-8 ?
The solutions to the equation 5(x^2-7)-8=-8 are x=sqrt(7),x=-sqrt(7)
Find the zeros of 5(x^2-7)-8=-8
The zeros of 5(x^2-7)-8=-8 are x=sqrt(7),x=-sqrt(7)