What are the solutions to the equation 3m^2+7m=7 ?

The solutions to the equation 3m^2+7m=7 are m=(-7+sqrt(133))/6 ,m=(-7-sqrt(133))/6

Find the zeros of 3m^2+7m=7

The zeros of 3m^2+7m=7 are m=(-7+sqrt(133))/6 ,m=(-7-sqrt(133))/6

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3 m^{2} + 7 m = 7

m = \frac{- 7 + 133}{6}, m = \frac{- 7 - 133}{6}

Decimal Notation

m = 0.75542 \dots, m = - 3.08876 \dots

Solution steps

3 m^{2} + 7 m = 7

Move

7

to the left side

3 m^{2} + 7 m - 7 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

7^{2} - 4 \cdot 3 (- 7) = 133

m_{1, 2} = \frac{- 7 \pm 133}{2 \cdot 3}

Separate the solutions

m_{1} = \frac{- 7 + 133}{2 \cdot 3}, m_{2} = \frac{- 7 - 133}{2 \cdot 3}

m = \frac{- 7 + 133}{2 \cdot 3} : \frac{- 7 + 133}{6}

m = \frac{- 7 - 133}{2 \cdot 3} : \frac{- 7 - 133}{6}

The solutions to the quadratic equation are:

m = \frac{- 7 + 133}{6}, m = \frac{- 7 - 133}{6}

3 p^{2} + p - 9 = 0

4 x^{2} - 4 x + 1

\frac{e ^{4} - e ^{- 4}}{2}

4 x^{2} - 9 x + 4 = 0

x

What are the solutions to the equation 3m^2+7m=7 ?
The solutions to the equation 3m^2+7m=7 are m=(-7+sqrt(133))/6 ,m=(-7-sqrt(133))/6
Find the zeros of 3m^2+7m=7
The zeros of 3m^2+7m=7 are m=(-7+sqrt(133))/6 ,m=(-7-sqrt(133))/6