What are the solutions to the equation 4u^2-6=5u ?

The solutions to the equation 4u^2-6=5u are u=2,u=-3/4

Find the zeros of 4u^2-6=5u

The zeros of 4u^2-6=5u are u=2,u=-3/4

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4 u^{2} - 6 = 5 u

u = 2, u = - \frac{3}{4}

Decimal Notation

u = 2, u = - 0.75

Solution steps

4 u^{2} - 6 = 5 u

Move

5 u

to the left side

4 u^{2} - 6 - 5 u = 0

Write in the standard form

a x^{2} + b x + c = 0

4 u^{2} - 5 u - 6 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 ( - 6 )}{2 \cdot 4}

(- 5)^{2} - 4 \cdot 4 (- 6) = 11

u_{1, 2} = \frac{- ( - 5 ) \pm 11}{2 \cdot 4}

Separate the solutions

u_{1} = \frac{- ( - 5 ) + 11}{2 \cdot 4}, u_{2} = \frac{- ( - 5 ) - 11}{2 \cdot 4}

u = \frac{- ( - 5 ) + 11}{2 \cdot 4} : 2

u = \frac{- ( - 5 ) - 11}{2 \cdot 4} : - \frac{3}{4}

The solutions to the quadratic equation are:

u = 2, u = - \frac{3}{4}

\frac{2}{3 - 1}

2 (- 9.8)

e^{\frac{iπ}{3}}

5 x^{2} + 15 x = 0

(- 8 k + 1) (- 8 k + 1) = (- 8 k + 1) (- 8 k + 1)

What are the solutions to the equation 4u^2-6=5u ?
The solutions to the equation 4u^2-6=5u are u=2,u=-3/4
Find the zeros of 4u^2-6=5u
The zeros of 4u^2-6=5u are u=2,u=-3/4