What are the solutions to the equation -x^2+8x-16=0 ?

The solutions to the equation -x^2+8x-16=0 are x=4

Find the zeros of -x^2+8x-16=0

The zeros of -x^2+8x-16=0 are x=4

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- x^{2} + 8 x - 16 = 0

x = 4

Solution steps

- x^{2} + 8 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) ( - 16 )}{2 ( - 1 )}

8^{2} - 4 (- 1) (- 16) = 0

x_{1, 2} = \frac{- 8 \pm 0}{2 ( - 1 )}

x = \frac{- 8}{2 ( - 1 )}

\frac{- 8}{2 ( - 1 )} = 4

x = 4

The solution to the quadratic equation is:

x = 4

x^{4} + 15 x^{2} + 56

- 7 \geq 5 w - 22

10 x^{3} - 15 x^{2} + 12 x - 18

4 (8)

32 \cdot 3

What are the solutions to the equation -x^2+8x-16=0 ?
The solutions to the equation -x^2+8x-16=0 are x=4
Find the zeros of -x^2+8x-16=0
The zeros of -x^2+8x-16=0 are x=4