What are the solutions to the equation n^2-28=0 ?

The solutions to the equation n^2-28=0 are n=2sqrt(7),n=-2sqrt(7)

Find the zeros of n^2-28=0

The zeros of n^2-28=0 are n=2sqrt(7),n=-2sqrt(7)

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n^{2} - 28 = 0

n = 27, n = - 27

Decimal Notation

n = 5.29150 \dots, n = - 5.29150 \dots

Solution steps

n^{2} - 28 = 0

Move

28

to the right side

n^{2} = 28

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = 28, n = - 28

28 = 27

- 28 = - 27

n = 27, n = - 27

\frac{12 !}{6 ! \cdot 6 !}

x + 1 = 7 x - 5

(\frac{7}{8})^{- 1}

- 3 x + 5 = - 8 x + 10

12 x^{2} + 17 x + 6

What are the solutions to the equation n^2-28=0 ?
The solutions to the equation n^2-28=0 are n=2sqrt(7),n=-2sqrt(7)
Find the zeros of n^2-28=0
The zeros of n^2-28=0 are n=2sqrt(7),n=-2sqrt(7)