What are the solutions to the equation s^2-4s+20=0 ?

The solutions to the equation s^2-4s+20=0 are s=2+4i,s=2-4i

Find the zeros of s^2-4s+20=0

The zeros of s^2-4s+20=0 are s=2+4i,s=2-4i

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s^{2} - 4 s + 20 = 0

s = 2 + 4 i, s = 2 - 4 i

Solution steps

s^{2} - 4 s + 20 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 20 : 8 i

s_{1, 2} = \frac{- ( - 4 ) \pm 8 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 4 ) + 8 i}{2 \cdot 1}, s_{2} = \frac{- ( - 4 ) - 8 i}{2 \cdot 1}

s = \frac{- ( - 4 ) + 8 i}{2 \cdot 1} : 2 + 4 i

s = \frac{- ( - 4 ) - 8 i}{2 \cdot 1} : 2 - 4 i

The solutions to the quadratic equation are:

s = 2 + 4 i, s = 2 - 4 i

3 x - 5 = - 11

x - 4 \leq 3 x + 8

(- 8)^{2}

2 x + 4 < 10

\frac{11 ( 0 ) + 195}{0 + 8}

What are the solutions to the equation s^2-4s+20=0 ?
The solutions to the equation s^2-4s+20=0 are s=2+4i,s=2-4i
Find the zeros of s^2-4s+20=0
The zeros of s^2-4s+20=0 are s=2+4i,s=2-4i