What are the solutions to the equation (x+9)^2+15(x+9)+56=0 ?

The solutions to the equation (x+9)^2+15(x+9)+56=0 are x=-16,x=-17

Find the zeros of (x+9)^2+15(x+9)+56=0

The zeros of (x+9)^2+15(x+9)+56=0 are x=-16,x=-17

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(x + 9)^{2} + 15 (x + 9) + 56 = 0

x = - 16, x = - 17

Solution steps

(x + 9)^{2} + 15 (x + 9) + 56 = 0

Expand

(x + 9)^{2} + 15 (x + 9) + 56 : x^{2} + 33 x + 272

x^{2} + 33 x + 272 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 33 \pm 3 3 ^{2} - 4 \cdot 1 \cdot 272}{2 \cdot 1}

3 3^{2} - 4 \cdot 1 \cdot 272 = 1

x_{1, 2} = \frac{- 33 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 33 + 1}{2 \cdot 1}, x_{2} = \frac{- 33 - 1}{2 \cdot 1}

x = \frac{- 33 + 1}{2 \cdot 1} : - 16

x = \frac{- 33 - 1}{2 \cdot 1} : - 17

The solutions to the quadratic equation are:

x = - 16, x = - 17

0 + \frac{1}{2}

9 x^{6} - y^{8}

\frac{5}{3 - 4 i}

c^{2} - (d - 5)^{2}

4 t - 0.8 t^{2} = 2.5

What are the solutions to the equation (x+9)^2+15(x+9)+56=0 ?
The solutions to the equation (x+9)^2+15(x+9)+56=0 are x=-16,x=-17
Find the zeros of (x+9)^2+15(x+9)+56=0
The zeros of (x+9)^2+15(x+9)+56=0 are x=-16,x=-17