What are the solutions to the equation 4x^2+3x+7=0 ?

The solutions to the equation 4x^2+3x+7=0 are x=-3/8+i(sqrt(103))/8 ,x=-3/8-i(sqrt(103))/8

Find the zeros of 4x^2+3x+7=0

The zeros of 4x^2+3x+7=0 are x=-3/8+i(sqrt(103))/8 ,x=-3/8-i(sqrt(103))/8

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4 x^{2} + 3 x + 7 = 0

x = - \frac{3}{8} + i \frac{103}{8}, x = - \frac{3}{8} - i \frac{103}{8}

Solution steps

4 x^{2} + 3 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 \cdot 7}{2 \cdot 4}

Simplify

3^{2} - 4 \cdot 4 \cdot 7 : 103 i

x_{1, 2} = \frac{- 3 \pm 103 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 3 + 103 i}{2 \cdot 4}, x_{2} = \frac{- 3 - 103 i}{2 \cdot 4}

x = \frac{- 3 + 103 i}{2 \cdot 4} : - \frac{3}{8} + i \frac{103}{8}

x = \frac{- 3 - 103 i}{2 \cdot 4} : - \frac{3}{8} - i \frac{103}{8}

The solutions to the quadratic equation are:

x = - \frac{3}{8} + i \frac{103}{8}, x = - \frac{3}{8} - i \frac{103}{8}

3 f + e = 6

\frac{( \frac{( 400 - 25 x ^{2} )}{4} )}{64} - \frac{( x ^{2} )}{25} = 1

3 - 12 \times 2 + 19

∣ x ∣ = ∣ - x ∣

\frac{637}{33 \cdot 10 \cdot 1.88}

What are the solutions to the equation 4x^2+3x+7=0 ?
The solutions to the equation 4x^2+3x+7=0 are x=-3/8+i(sqrt(103))/8 ,x=-3/8-i(sqrt(103))/8
Find the zeros of 4x^2+3x+7=0
The zeros of 4x^2+3x+7=0 are x=-3/8+i(sqrt(103))/8 ,x=-3/8-i(sqrt(103))/8