What are the solutions to the equation 0=a^2+4a-2 ?

The solutions to the equation 0=a^2+4a-2 are a=-2+sqrt(6),a=-2-sqrt(6)

Find the zeros of 0=a^2+4a-2

The zeros of 0=a^2+4a-2 are a=-2+sqrt(6),a=-2-sqrt(6)

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0 = a^{2} + 4 a - 2

a = - 2 + 6, a = - 2 - 6

Decimal Notation

a = 0.44948 \dots, a = - 4.44948 \dots

Solution steps

0 = a^{2} + 4 a - 2

Switch sides

a^{2} + 4 a - 2 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 2) = 26

a_{1, 2} = \frac{- 4 \pm 2 6}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 4 + 2 6}{2 \cdot 1}, a_{2} = \frac{- 4 - 2 6}{2 \cdot 1}

a = \frac{- 4 + 2 6}{2 \cdot 1} : - 2 + 6

a = \frac{- 4 - 2 6}{2 \cdot 1} : - 2 - 6

The solutions to the quadratic equation are:

a = - 2 + 6, a = - 2 - 6

- 33 \leq - 7 n - 12 < - 26

\frac{10 - 4}{10}

3 x + 9 = - 36

r^{2} - 4 r = 30

\frac{x - 5}{2} = \frac{2 x - 1}{7}

What are the solutions to the equation 0=a^2+4a-2 ?
The solutions to the equation 0=a^2+4a-2 are a=-2+sqrt(6),a=-2-sqrt(6)
Find the zeros of 0=a^2+4a-2
The zeros of 0=a^2+4a-2 are a=-2+sqrt(6),a=-2-sqrt(6)