What are the solutions to the equation (3/2 x-3)(4x+5)=0 ?

The solutions to the equation (3/2 x-3)(4x+5)=0 are x=2,x=-5/4

Find the zeros of (3/2 x-3)(4x+5)=0

The zeros of (3/2 x-3)(4x+5)=0 are x=2,x=-5/4

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(\frac{3}{2} x - 3) (4 x + 5) = 0

x = 2, x = - \frac{5}{4}

Decimal Notation

x = 2, x = - 1.25

Solution steps

(\frac{3}{2} x - 3) (4 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

\frac{3}{2} x - 3 = 0 or 4 x + 5 = 0

Solve

\frac{3}{2} x - 3 = 0 : x = 2

Solve

4 x + 5 = 0 : x = - \frac{5}{4}

The solutions to the quadratic equation are:

x = 2, x = - \frac{5}{4}

(\frac{1}{4})^{- \frac{5}{2}}

x - 60 = 80

42 = 7 (p - 13)

- 2 (12 x + 2) + 9 = 6 (- 4 x + 1) - 11

\frac{i ^{4} - i ^{2}}{i ^{3}}

What are the solutions to the equation (3/2 x-3)(4x+5)=0 ?
The solutions to the equation (3/2 x-3)(4x+5)=0 are x=2,x=-5/4
Find the zeros of (3/2 x-3)(4x+5)=0
The zeros of (3/2 x-3)(4x+5)=0 are x=2,x=-5/4