What are the solutions to the equation 2x^2-16x+24=0 ?

The solutions to the equation 2x^2-16x+24=0 are x=6,x=2

Find the zeros of 2x^2-16x+24=0

The zeros of 2x^2-16x+24=0 are x=6,x=2

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2 x^{2} - 16 x + 24 = 0

x = 6, x = 2

Solution steps

2 x^{2} - 16 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 2 \cdot 24}{2 \cdot 2}

(- 16)^{2} - 4 \cdot 2 \cdot 24 = 8

x_{1, 2} = \frac{- ( - 16 ) \pm 8}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 8}{2 \cdot 2}, x_{2} = \frac{- ( - 16 ) - 8}{2 \cdot 2}

x = \frac{- ( - 16 ) + 8}{2 \cdot 2} : 6

x = \frac{- ( - 16 ) - 8}{2 \cdot 2} : 2

The solutions to the quadratic equation are:

x = 6, x = 2

- 4 x^{4} y^{2} + 8 y + 8

2^{- 4}

\frac{5 p}{2 q - p} + \frac{10 p}{p - 2 q}

- 76 x + 76 = 76 x + 76

\frac{3}{2} - \frac{5}{6}

What are the solutions to the equation 2x^2-16x+24=0 ?
The solutions to the equation 2x^2-16x+24=0 are x=6,x=2
Find the zeros of 2x^2-16x+24=0
The zeros of 2x^2-16x+24=0 are x=6,x=2