What is factor 1/16 x^4+4x^2+64 ?

The solution to factor 1/16 x^4+4x^2+64 is ((x^2)/4+8)^2

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factor 1/16 x^4+4x^2+64

factor

\frac{1}{16} x^{4} + 4 x^{2} + 64

(\frac{x ^{2}}{4} + 8)^{2}

Solution steps

\frac{1}{16} x^{4} + 4 x^{2} + 64

Let

u = x^{2}

= \frac{u ^{2}}{16} + 4 u + 64

Factor

\frac{u ^{2}}{16} + 4 u + 64 : (\frac{u}{4} + 8)^{2}

= (\frac{u}{4} + 8)^{2}

Substitute back

u = x^{2}

= (\frac{x ^{2}}{4} + 8)^{2}

\frac{1}{2} x^{2} + 3 x - 3.5

i

x (x - 2) = 0

- 2 ∣ x + 3 ∣ + 10 = - 4

x^{4} - 19 x^{3} + 135 x^{2} - 425 x + 500

What is factor 1/16 x^4+4x^2+64 ?
The solution to factor 1/16 x^4+4x^2+64 is ((x^2)/4+8)^2