What are the solutions to the equation a^2-8a+15=0 ?

The solutions to the equation a^2-8a+15=0 are a=5,a=3

Find the zeros of a^2-8a+15=0

The zeros of a^2-8a+15=0 are a=5,a=3

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a^{2} - 8 a + 15 = 0

a = 5, a = 3

Solution steps

a^{2} - 8 a + 15 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

a_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, a_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

a = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

a = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

a = 5, a = 3

4 x = 4 x

- (6.24 c - 4.71) + 5.24 c = - 7.93

15 x - 13 < 77

254

3 x^{2} - 24 x = - 48

What are the solutions to the equation a^2-8a+15=0 ?
The solutions to the equation a^2-8a+15=0 are a=5,a=3
Find the zeros of a^2-8a+15=0
The zeros of a^2-8a+15=0 are a=5,a=3