What is factor ((x^4+x^3+8x^2-x+1))/((x^2-1)) ?

The solution to factor ((x^4+x^3+8x^2-x+1))/((x^2-1)) is (x^4+x^3+8x^2-x+1)/((x+1)(x-1))

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factor ((x^4+x^3+8x^2-x+1))/((x^2-1))

factor

\frac{( x ^{4} + x ^{3} + 8 x ^{2} - x + 1 )}{( x ^{2} - 1 )}

\frac{x ^{4} + x ^{3} + 8 x ^{2} - x + 1}{( x + 1 ) ( x - 1 )}

Solution steps

\frac{x ^{4} + x ^{3} + 8 x ^{2} - x + 1}{x ^{2} - 1}

Factor

x^{2} - 1 : (x + 1) (x - 1)

= \frac{x ^{4} + x ^{3} + 8 x ^{2} - x + 1}{( x + 1 ) ( x - 1 )}

x^{4} - 6561

\frac{1}{5} (x - 12) = \frac{1}{4} (x - 15)

\frac{2 ( 4 ) ^{\frac{3}{2}}}{3}

\frac{6}{5}

8 \times \frac{1}{2}

What is factor ((x^4+x^3+8x^2-x+1))/((x^2-1)) ?
The solution to factor ((x^4+x^3+8x^2-x+1))/((x^2-1)) is (x^4+x^3+8x^2-x+1)/((x+1)(x-1))