What are the solutions to the equation x+2=x^2-3x+5 ?

The solutions to the equation x+2=x^2-3x+5 are x=3,x=1

Find the zeros of x+2=x^2-3x+5

The zeros of x+2=x^2-3x+5 are x=3,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x + 2 = x^{2} - 3 x + 5

x = 3, x = 1

Solution steps

x + 2 = x^{2} - 3 x + 5

Switch sides

x^{2} - 3 x + 5 = x + 2

Move

2

to the left side

x^{2} - 3 x + 3 = x

Move

x

to the left side

x^{2} - 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 3 = 2

x_{1, 2} = \frac{- ( - 4 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2}{2 \cdot 1} : 3

x = \frac{- ( - 4 ) - 2}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 3, x = 1

x^{3} - 8 \geq 0

2 7^{- \frac{4}{3}}

x y + 4 y - 2 x - 8

(\frac{5}{6} x + 3)^{2} = 5 x + 8

(- 1 + i)^{2}

What are the solutions to the equation x+2=x^2-3x+5 ?
The solutions to the equation x+2=x^2-3x+5 are x=3,x=1
Find the zeros of x+2=x^2-3x+5
The zeros of x+2=x^2-3x+5 are x=3,x=1