What are the solutions to the equation solvefor y,x^3-x^2+2xy-y^2=0 ?

The solutions to the equation solvefor y,x^3-x^2+2xy-y^2=0 are y=-x(sqrt(x)-1),y=x(sqrt(x)+1)

Find the zeros of solvefor y,x^3-x^2+2xy-y^2=0

The zeros of solvefor y,x^3-x^2+2xy-y^2=0 are y=-x(sqrt(x)-1),y=x(sqrt(x)+1)

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solve for

y, x^{3} - x^{2} + 2 x y - y^{2} = 0

y = - x (x - 1), y = x (x + 1)

Solution steps

x^{3} - x^{2} + 2 x y - y^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- y^{2} + 2 x y + x^{3} - x^{2} = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 2 x \pm ( 2 x ) ^{2} - 4 ( - 1 ) ( x ^{3} - x ^{2} )}{2 ( - 1 )}

Simplify

(2 x)^{2} - 4 (- 1) (x^{3} - x^{2}) : 2 x x

y_{1, 2} = \frac{- 2 x \pm 2 x x}{2 ( - 1 )}

Separate the solutions

y_{1} = \frac{- 2 x + 2 x x}{2 ( - 1 )}, y_{2} = \frac{- 2 x - 2 x x}{2 ( - 1 )}

y = \frac{- 2 x + 2 x x}{2 ( - 1 )} : - x (x - 1)

y = \frac{- 2 x - 2 x x}{2 ( - 1 )} : x (x + 1)

The solutions to the quadratic equation are:

y = - x (x - 1), y = x (x + 1)

5 x - 15 > - 65

10 y + 4 - 7 y = - 17

- 2 (y + 1) + 5 y = 3 (y + 1) - 2

2 (x + 3) = 16

lo g_{16} (\frac{1}{4}) = x

What are the solutions to the equation solvefor y,x^3-x^2+2xy-y^2=0 ?
The solutions to the equation solvefor y,x^3-x^2+2xy-y^2=0 are y=-x(sqrt(x)-1),y=x(sqrt(x)+1)
Find the zeros of solvefor y,x^3-x^2+2xy-y^2=0
The zeros of solvefor y,x^3-x^2+2xy-y^2=0 are y=-x(sqrt(x)-1),y=x(sqrt(x)+1)