What are the solutions to the equation 3x^2+7x=-2 ?

The solutions to the equation 3x^2+7x=-2 are x=-1/3 ,x=-2

Find the zeros of 3x^2+7x=-2

The zeros of 3x^2+7x=-2 are x=-1/3 ,x=-2

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3 x^{2} + 7 x = - 2

x = - \frac{1}{3}, x = - 2

Decimal

x = - 0.33333 \dots, x = - 2

Solution steps

3 x^{2} + 7 x = - 2

Move

2

to the left side

3 x^{2} + 7 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

7^{2} - 4 \cdot 3 \cdot 2 = 5

x_{1, 2} = \frac{- 7 \pm 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 7 + 5}{2 \cdot 3}, x_{2} = \frac{- 7 - 5}{2 \cdot 3}

x = \frac{- 7 + 5}{2 \cdot 3} : - \frac{1}{3}

x = \frac{- 7 - 5}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - 2

- 2 (5 - x) = 6 - 6 x

9 x^{2} + 9 x - 4

x + 7 - \frac{3}{2} x - \frac{x + 3}{3} = \frac{3}{4} (2 x - 5) + 1

21 x^{2} - 37 x + 12

15 x^{2} + 5 x - 50

What are the solutions to the equation 3x^2+7x=-2 ?
The solutions to the equation 3x^2+7x=-2 are x=-1/3 ,x=-2
Find the zeros of 3x^2+7x=-2
The zeros of 3x^2+7x=-2 are x=-1/3 ,x=-2