What are the solutions to the equation 12=6t^2+6t ?

The solutions to the equation 12=6t^2+6t are t=1,t=-2

Find the zeros of 12=6t^2+6t

The zeros of 12=6t^2+6t are t=1,t=-2

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12 = 6 t^{2} + 6 t

t = 1, t = - 2

Solution steps

12 = 6 t^{2} + 6 t

Switch sides

6 t^{2} + 6 t = 12

Move

12

to the left side

6 t^{2} + 6 t - 12 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 6 ( - 12 )}{2 \cdot 6}

6^{2} - 4 \cdot 6 (- 12) = 18

t_{1, 2} = \frac{- 6 \pm 18}{2 \cdot 6}

Separate the solutions

t_{1} = \frac{- 6 + 18}{2 \cdot 6}, t_{2} = \frac{- 6 - 18}{2 \cdot 6}

t = \frac{- 6 + 18}{2 \cdot 6} : 1

t = \frac{- 6 - 18}{2 \cdot 6} : - 2

The solutions to the quadratic equation are:

t = 1, t = - 2

\frac{1}{3} \cdot \frac{4}{5}

∣ 3 x - 1 ∣ = 3

\frac{1}{x} \leq \frac{1}{2}

\frac{3 - 2 x}{5} - 3 < 6

- ln (\frac{2}{2})

What are the solutions to the equation 12=6t^2+6t ?
The solutions to the equation 12=6t^2+6t are t=1,t=-2
Find the zeros of 12=6t^2+6t
The zeros of 12=6t^2+6t are t=1,t=-2