What are the solutions to the equation 2x^2-14x+24=0 ?

The solutions to the equation 2x^2-14x+24=0 are x=4,x=3

Find the zeros of 2x^2-14x+24=0

The zeros of 2x^2-14x+24=0 are x=4,x=3

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2 x^{2} - 14 x + 24 = 0

x = 4, x = 3

Solution steps

2 x^{2} - 14 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 2 \cdot 24}{2 \cdot 2}

(- 14)^{2} - 4 \cdot 2 \cdot 24 = 2

x_{1, 2} = \frac{- ( - 14 ) \pm 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2}{2 \cdot 2}, x_{2} = \frac{- ( - 14 ) - 2}{2 \cdot 2}

x = \frac{- ( - 14 ) + 2}{2 \cdot 2} : 4

x = \frac{- ( - 14 ) - 2}{2 \cdot 2} : 3

The solutions to the quadratic equation are:

x = 4, x = 3

(x^{3})^{6}

4 a + 28 a + 49

i^{53}

\frac{1}{1 - 0.5}

2.7 = - 0.9 y

What are the solutions to the equation 2x^2-14x+24=0 ?
The solutions to the equation 2x^2-14x+24=0 are x=4,x=3
Find the zeros of 2x^2-14x+24=0
The zeros of 2x^2-14x+24=0 are x=4,x=3