What are the solutions to the equation 2x^2-10x+4=0 ?

The solutions to the equation 2x^2-10x+4=0 are x=(5+sqrt(17))/2 ,x=(5-sqrt(17))/2

Find the zeros of 2x^2-10x+4=0

The zeros of 2x^2-10x+4=0 are x=(5+sqrt(17))/2 ,x=(5-sqrt(17))/2

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2 x^{2} - 10 x + 4 = 0

x = \frac{5 + 17}{2}, x = \frac{5 - 17}{2}

Decimal Notation

x = 4.56155 \dots, x = 0.43844 \dots

Solution steps

2 x^{2} - 10 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 2 \cdot 4}{2 \cdot 2}

(- 10)^{2} - 4 \cdot 2 \cdot 4 = 217

x_{1, 2} = \frac{- ( - 10 ) \pm 2 17}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 17}{2 \cdot 2}, x_{2} = \frac{- ( - 10 ) - 2 17}{2 \cdot 2}

x = \frac{- ( - 10 ) + 2 17}{2 \cdot 2} : \frac{5 + 17}{2}

x = \frac{- ( - 10 ) - 2 17}{2 \cdot 2} : \frac{5 - 17}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 17}{2}, x = \frac{5 - 17}{2}

\frac{( x ^{- 1} + y ^{- 1} )}{2 x ^{- 1}}

2 x^{2} + 10 x = 28

(26 + 8) (26 - 8)

(2^{8})^{2}

What are the solutions to the equation 2x^2-10x+4=0 ?
The solutions to the equation 2x^2-10x+4=0 are x=(5+sqrt(17))/2 ,x=(5-sqrt(17))/2
Find the zeros of 2x^2-10x+4=0
The zeros of 2x^2-10x+4=0 are x=(5+sqrt(17))/2 ,x=(5-sqrt(17))/2