What are the solutions to the equation 3v^2=-v ?

The solutions to the equation 3v^2=-v are v=0,v=-1/3

Find the zeros of 3v^2=-v

The zeros of 3v^2=-v are v=0,v=-1/3

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3 v^{2} = - v

v = 0, v = - \frac{1}{3}

Decimal Notation

v = 0, v = - 0.33333 \dots

Solution steps

3 v^{2} = - v

Move

v

to the left side

3 v^{2} + v = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

1^{2} - 4 \cdot 3 \cdot 0 = 1

v_{1, 2} = \frac{- 1 \pm 1}{2 \cdot 3}

Separate the solutions

v_{1} = \frac{- 1 + 1}{2 \cdot 3}, v_{2} = \frac{- 1 - 1}{2 \cdot 3}

v = \frac{- 1 + 1}{2 \cdot 3} : 0

v = \frac{- 1 - 1}{2 \cdot 3} : - \frac{1}{3}

The solutions to the quadratic equation are:

v = 0, v = - \frac{1}{3}

\frac{( x - 1 )}{x} - \frac{( x + 1 )}{x - 1} < 2

50 m^{2} - 18 n^{2}

5 y^{2} - 6 y + 1

x^{2} + 17 x + 72

6 x^{2} - 54 = 0

What are the solutions to the equation 3v^2=-v ?
The solutions to the equation 3v^2=-v are v=0,v=-1/3
Find the zeros of 3v^2=-v
The zeros of 3v^2=-v are v=0,v=-1/3