What are the solutions to the equation x^2-4x+4=100 ?

The solutions to the equation x^2-4x+4=100 are x=12,x=-8

Find the zeros of x^2-4x+4=100

The zeros of x^2-4x+4=100 are x=12,x=-8

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x^{2} - 4 x + 4 = 100

x = 12, x = - 8

Solution steps

x^{2} - 4 x + 4 = 100

Move

100

to the left side

x^{2} - 4 x - 96 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 96 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 96) = 20

x_{1, 2} = \frac{- ( - 4 ) \pm 20}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 20}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 20}{2 \cdot 1}

x = \frac{- ( - 4 ) + 20}{2 \cdot 1} : 12

x = \frac{- ( - 4 ) - 20}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 12, x = - 8

(x + 7)^{2} = 36

\frac{12 !}{3 !}

\frac{8}{8}

- 30 x - 6 = - 66

2 + \frac{1}{3} x = x - 5

What are the solutions to the equation x^2-4x+4=100 ?
The solutions to the equation x^2-4x+4=100 are x=12,x=-8
Find the zeros of x^2-4x+4=100
The zeros of x^2-4x+4=100 are x=12,x=-8