What are the solutions to the equation 3x^2-6x+7=0 ?

The solutions to the equation 3x^2-6x+7=0 are x=1+i(2sqrt(3))/3 ,x=1-i(2sqrt(3))/3

Find the zeros of 3x^2-6x+7=0

The zeros of 3x^2-6x+7=0 are x=1+i(2sqrt(3))/3 ,x=1-i(2sqrt(3))/3

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3 x^{2} - 6 x + 7 = 0

x = 1 + i \frac{2 3}{3}, x = 1 - i \frac{2 3}{3}

Solution steps

3 x^{2} - 6 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 \cdot 7}{2 \cdot 3}

Simplify

(- 6)^{2} - 4 \cdot 3 \cdot 7 : 43 i

x_{1, 2} = \frac{- ( - 6 ) \pm 4 3 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 4 3 i}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 4 3 i}{2 \cdot 3}

x = \frac{- ( - 6 ) + 4 3 i}{2 \cdot 3} : 1 + i \frac{2 3}{3}

x = \frac{- ( - 6 ) - 4 3 i}{2 \cdot 3} : 1 - i \frac{2 3}{3}

The solutions to the quadratic equation are:

x = 1 + i \frac{2 3}{3}, x = 1 - i \frac{2 3}{3}

- 2 x + 5 > 16

14 - x > 8

2 < (x + 1)^{2} + 1 \leq 10

2 (12 - y) = 23 - (2 y - 1)

(x - 3) (x + 1) \leq 0

What are the solutions to the equation 3x^2-6x+7=0 ?
The solutions to the equation 3x^2-6x+7=0 are x=1+i(2sqrt(3))/3 ,x=1-i(2sqrt(3))/3
Find the zeros of 3x^2-6x+7=0
The zeros of 3x^2-6x+7=0 are x=1+i(2sqrt(3))/3 ,x=1-i(2sqrt(3))/3