What are the solutions to the equation -3x^2+6x-3=0 ?

The solutions to the equation -3x^2+6x-3=0 are x=1

Find the zeros of -3x^2+6x-3=0

The zeros of -3x^2+6x-3=0 are x=1

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- 3 x^{2} + 6 x - 3 = 0

x = 1

Solution steps

- 3 x^{2} + 6 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 3 ) ( - 3 )}{2 ( - 3 )}

6^{2} - 4 (- 3) (- 3) = 0

x_{1, 2} = \frac{- 6 \pm 0}{2 ( - 3 )}

x = \frac{- 6}{2 ( - 3 )}

\frac{- 6}{2 ( - 3 )} = 1

x = 1

The solution to the quadratic equation is:

x = 1

4 x - 22 = - 2

\frac{j}{3} > 3

x^{2} + 2 x + 4 > 0

12 - 13 x \geq - 1

18 = - 9 - 3 y

What are the solutions to the equation -3x^2+6x-3=0 ?
The solutions to the equation -3x^2+6x-3=0 are x=1
Find the zeros of -3x^2+6x-3=0
The zeros of -3x^2+6x-3=0 are x=1