What are the solutions to the equation x^2+12x+36=-88 ?

The solutions to the equation x^2+12x+36=-88 are x=-6+2sqrt(22)i,x=-6-2sqrt(22)i

Find the zeros of x^2+12x+36=-88

The zeros of x^2+12x+36=-88 are x=-6+2sqrt(22)i,x=-6-2sqrt(22)i

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x^{2} + 12 x + 36 = - 88

x = - 6 + 222 i, x = - 6 - 222 i

Solution steps

x^{2} + 12 x + 36 = - 88

Move

88

to the left side

x^{2} + 12 x + 124 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 124}{2 \cdot 1}

Simplify

1 2^{2} - 4 \cdot 1 \cdot 124 : 422 i

x_{1, 2} = \frac{- 12 \pm 4 22 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 4 22 i}{2 \cdot 1}, x_{2} = \frac{- 12 - 4 22 i}{2 \cdot 1}

x = \frac{- 12 + 4 22 i}{2 \cdot 1} : - 6 + 222 i

x = \frac{- 12 - 4 22 i}{2 \cdot 1} : - 6 - 222 i

The solutions to the quadratic equation are:

x = - 6 + 222 i, x = - 6 - 222 i

(\frac{1}{9} m + \frac{2}{7} n) (\frac{1}{9} m - \frac{1}{3})

5 y + 6 = 9 y + 30

3 x^{2} = 21

\frac{2}{3} x - 3 = 19

130510.7749 (0.00192 \cdot 2) = 0.14 \cdot 8.31 \cdot t

What are the solutions to the equation x^2+12x+36=-88 ?
The solutions to the equation x^2+12x+36=-88 are x=-6+2sqrt(22)i,x=-6-2sqrt(22)i
Find the zeros of x^2+12x+36=-88
The zeros of x^2+12x+36=-88 are x=-6+2sqrt(22)i,x=-6-2sqrt(22)i