What are the solutions to the equation 6p^2+25p-119=0 ?

The solutions to the equation 6p^2+25p-119=0 are p= 17/6 ,p=-7

Find the zeros of 6p^2+25p-119=0

The zeros of 6p^2+25p-119=0 are p= 17/6 ,p=-7

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6 p^{2} + 25 p - 119 = 0

p = \frac{17}{6}, p = - 7

Solution steps

6 p^{2} + 25 p - 119 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 \cdot 6 ( - 119 )}{2 \cdot 6}

2 5^{2} - 4 \cdot 6 (- 119) = 59

p_{1, 2} = \frac{- 25 \pm 59}{2 \cdot 6}

Separate the solutions

p_{1} = \frac{- 25 + 59}{2 \cdot 6}, p_{2} = \frac{- 25 - 59}{2 \cdot 6}

p = \frac{- 25 + 59}{2 \cdot 6} : \frac{17}{6}

p = \frac{- 25 - 59}{2 \cdot 6} : - 7

The solutions to the quadratic equation are:

p = \frac{17}{6}, p = - 7

p^{2} + 2 p - 35

15 c^{- 8} d^{0}

- 1 \leq \frac{t}{2} + 1

\frac{3}{4} - \frac{7}{10}

\frac{b ^{2}}{b ^{4}}

What are the solutions to the equation 6p^2+25p-119=0 ?
The solutions to the equation 6p^2+25p-119=0 are p= 17/6 ,p=-7
Find the zeros of 6p^2+25p-119=0
The zeros of 6p^2+25p-119=0 are p= 17/6 ,p=-7