What are the solutions to the equation -2x^2+146=-34 ?

The solutions to the equation -2x^2+146=-34 are x=3sqrt(10),x=-3sqrt(10)

Find the zeros of -2x^2+146=-34

The zeros of -2x^2+146=-34 are x=3sqrt(10),x=-3sqrt(10)

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- 2 x^{2} + 146 = - 34

x = 310, x = - 310

Solution steps

- 2 x^{2} + 146 = - 34

Move

146

to the right side

- 2 x^{2} = - 180

Divide both sides by

- 2

x^{2} = 90

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 90, x = - 90

90 = 310

- 90 = - 310

x = 310, x = - 310

2 x^{2} + 8 x + 912 = 0

x y

512 m^{3}

\frac{( x y ^{2} z ^{3} ) ^{4}}{( x ^{3} y ^{2} z ) ^{3}}

2904

What are the solutions to the equation -2x^2+146=-34 ?
The solutions to the equation -2x^2+146=-34 are x=3sqrt(10),x=-3sqrt(10)
Find the zeros of -2x^2+146=-34
The zeros of -2x^2+146=-34 are x=3sqrt(10),x=-3sqrt(10)