What are the solutions to the equation sqrt(40)^2+3^2=c^2 ?

The solutions to the equation sqrt(40)^2+3^2=c^2 are c=7,c=-7

Find the zeros of sqrt(40)^2+3^2=c^2

The zeros of sqrt(40)^2+3^2=c^2 are c=7,c=-7

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40^{2} + 3^{2} = c^{2}

c = 7, c = - 7

Solution steps

(40)^{2} + 3^{2} = c^{2}

Switch sides

c^{2} = (40)^{2} + 3^{2}

Simplify

(40)^{2} + 3^{2} : 49

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 49, c = - 49

49 = 7

- 49 = - 7

c = 7, c = - 7

x^{4} + 9 \geq 10 x^{2}

80 t^{2} - 45

\frac{( 0.2431 - 2.4808 i )}{5}

- 9 + 3 = x

\frac{500000}{x ^{2} + 400} < 210

What are the solutions to the equation sqrt(40)^2+3^2=c^2 ?
The solutions to the equation sqrt(40)^2+3^2=c^2 are c=7,c=-7
Find the zeros of sqrt(40)^2+3^2=c^2
The zeros of sqrt(40)^2+3^2=c^2 are c=7,c=-7