What are the solutions to the equation 3v^2+36v+49=8v ?

The solutions to the equation 3v^2+36v+49=8v are v=-7/3 ,v=-7

Find the zeros of 3v^2+36v+49=8v

The zeros of 3v^2+36v+49=8v are v=-7/3 ,v=-7

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3 v^{2} + 36 v + 49 = 8 v

v = - \frac{7}{3}, v = - 7

Decimal Notation

v = - 2.33333 \dots, v = - 7

Solution steps

3 v^{2} + 36 v + 49 = 8 v

Move

8 v

to the left side

3 v^{2} + 28 v + 49 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 3 \cdot 49}{2 \cdot 3}

2 8^{2} - 4 \cdot 3 \cdot 49 = 14

v_{1, 2} = \frac{- 28 \pm 14}{2 \cdot 3}

Separate the solutions

v_{1} = \frac{- 28 + 14}{2 \cdot 3}, v_{2} = \frac{- 28 - 14}{2 \cdot 3}

v = \frac{- 28 + 14}{2 \cdot 3} : - \frac{7}{3}

v = \frac{- 28 - 14}{2 \cdot 3} : - 7

The solutions to the quadratic equation are:

v = - \frac{7}{3}, v = - 7

\frac{5}{6} - 2

2 x^{2} + 15 x + 2 = 4 x - 3

(5 x + 2)^{2} = 10

7 x - 3 = 3 x + 17

3 c^{2} + 4 c + 8 = 6 c

What are the solutions to the equation 3v^2+36v+49=8v ?
The solutions to the equation 3v^2+36v+49=8v are v=-7/3 ,v=-7
Find the zeros of 3v^2+36v+49=8v
The zeros of 3v^2+36v+49=8v are v=-7/3 ,v=-7