What are the solutions to the equation x^2+3x=28 ?

The solutions to the equation x^2+3x=28 are x=4,x=-7

Find the zeros of x^2+3x=28

The zeros of x^2+3x=28 are x=4,x=-7

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x^{2} + 3 x = 28

x = 4, x = - 7

Solution steps

x^{2} + 3 x = 28

Move

28

to the left side

x^{2} + 3 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 28 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 28) = 11

x_{1, 2} = \frac{- 3 \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 11}{2 \cdot 1}, x_{2} = \frac{- 3 - 11}{2 \cdot 1}

x = \frac{- 3 + 11}{2 \cdot 1} : 4

x = \frac{- 3 - 11}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 4, x = - 7

x^{2} + 18 x + 17

a^{2} \cdot a^{2}

3 y - 58 + y = 180

1 - 0.06

(x + 2) (x + 1) = 0

What are the solutions to the equation x^2+3x=28 ?
The solutions to the equation x^2+3x=28 are x=4,x=-7
Find the zeros of x^2+3x=28
The zeros of x^2+3x=28 are x=4,x=-7