What is factor x^3y-8+8y-x^3 ?

The solution to factor x^3y-8+8y-x^3 is (y-1)(x+2)(x^2-2x+4)

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factor x^3y-8+8y-x^3

factor

x^{3} y - 8 + 8 y - x^{3}

(y - 1) (x + 2) (x^{2} - 2 x + 4)

Solution steps

x^{3} y - 8 + 8 y - x^{3}

Group by common factors

= x^{3} y - x^{3} + 8 y - 8

= (x^{3} y - x^{3}) + (8 y - 8)

Factor out

x^{3}

from

x^{3} y - x^{3} : x^{3} (y - 1)

Factor out

8

from

8 y - 8 : 8 (y - 1)

= x^{3} (y - 1) + 8 (y - 1)

Factor out common term

y - 1

= (y - 1) (x^{3} + 8)

Factor

x^{3} + 8 : (x + 2) (x^{2} - 2 x + 2^{2})

= (y - 1) (x + 2) (x^{2} - 2 x + 2^{2})

2^{2} = 4

= (y - 1) (x + 2) (x^{2} - 2 x + 4)

\frac{1}{2} x + \frac{1}{4} = x

x - \frac{5}{3} \leq \frac{( 5 x - 1 )}{3}

\frac{x}{9} + \frac{x}{8} = \frac{17}{72}

lo g_{2} (6)

x^{2} - 11 = 0

What is factor x^3y-8+8y-x^3 ?
The solution to factor x^3y-8+8y-x^3 is (y-1)(x+2)(x^2-2x+4)