What are the solutions to the equation 8x^2+5x+13/4 =0 ?

The solutions to the equation 8x^2+5x+13/4 =0 are x=-5/16+i(sqrt(79))/(16),x=-5/16-i(sqrt(79))/(16)

Find the zeros of 8x^2+5x+13/4 =0

The zeros of 8x^2+5x+13/4 =0 are x=-5/16+i(sqrt(79))/(16),x=-5/16-i(sqrt(79))/(16)

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8 x^{2} + 5 x + \frac{13}{4} = 0

x = - \frac{5}{16} + i \frac{79}{16}, x = - \frac{5}{16} - i \frac{79}{16}

Solution steps

8 x^{2} + 5 x + \frac{13}{4} = 0

Multiply both sides by

4

32 x^{2} + 20 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 32 \cdot 13}{2 \cdot 32}

Simplify

2 0^{2} - 4 \cdot 32 \cdot 13 : 479 i

x_{1, 2} = \frac{- 20 \pm 4 79 i}{2 \cdot 32}

Separate the solutions

x_{1} = \frac{- 20 + 4 79 i}{2 \cdot 32}, x_{2} = \frac{- 20 - 4 79 i}{2 \cdot 32}

x = \frac{- 20 + 4 79 i}{2 \cdot 32} : - \frac{5}{16} + i \frac{79}{16}

x = \frac{- 20 - 4 79 i}{2 \cdot 32} : - \frac{5}{16} - i \frac{79}{16}

The solutions to the quadratic equation are:

x = - \frac{5}{16} + i \frac{79}{16}, x = - \frac{5}{16} - i \frac{79}{16}

(X + 7)^{2} + 12 = 0

(\frac{2}{2})^{2}

6 x^{2} - 14 x + 8

- 18 + n \leq - 7

What are the solutions to the equation 8x^2+5x+13/4 =0 ?
The solutions to the equation 8x^2+5x+13/4 =0 are x=-5/16+i(sqrt(79))/(16),x=-5/16-i(sqrt(79))/(16)
Find the zeros of 8x^2+5x+13/4 =0
The zeros of 8x^2+5x+13/4 =0 are x=-5/16+i(sqrt(79))/(16),x=-5/16-i(sqrt(79))/(16)