What are the solutions to the equation (3x-4)^2=8 ?

The solutions to the equation (3x-4)^2=8 are x=(2sqrt(2)+4)/3 ,x=(-2sqrt(2)+4)/3

Find the zeros of (3x-4)^2=8

The zeros of (3x-4)^2=8 are x=(2sqrt(2)+4)/3 ,x=(-2sqrt(2)+4)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(3 x - 4)^{2} = 8

x = \frac{2 2 + 4}{3}, x = \frac{- 2 2 + 4}{3}

Decimal Notation

x = 2.27614 \dots, x = 0.39052 \dots

Solution steps

(3 x - 4)^{2} = 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 4 = 8 : x = \frac{2 2 + 4}{3}

Solve

3 x - 4 = - 8 : x = \frac{- 2 2 + 4}{3}

The solutions to the quadratic equation are:

x = \frac{2 2 + 4}{3}, x = \frac{- 2 2 + 4}{3}

0 = x + 0.15 x^{2}

\frac{2 ^{- \frac{4}{3}}}{5 4 ^{- \frac{4}{3}}}

14 \cdot 2

x \geq \frac{8}{2 + x}

\frac{2 x + 1}{3} - \frac{4 - x}{6} = - 2

What are the solutions to the equation (3x-4)^2=8 ?
The solutions to the equation (3x-4)^2=8 are x=(2sqrt(2)+4)/3 ,x=(-2sqrt(2)+4)/3
Find the zeros of (3x-4)^2=8
The zeros of (3x-4)^2=8 are x=(2sqrt(2)+4)/3 ,x=(-2sqrt(2)+4)/3