What are the solutions to the equation x^2-27x+176=0 ?

The solutions to the equation x^2-27x+176=0 are x=16,x=11

Find the zeros of x^2-27x+176=0

The zeros of x^2-27x+176=0 are x=16,x=11

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x^{2} - 27 x + 176 = 0

x = 16, x = 11

Solution steps

x^{2} - 27 x + 176 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 1 \cdot 176}{2 \cdot 1}

(- 27)^{2} - 4 \cdot 1 \cdot 176 = 5

x_{1, 2} = \frac{- ( - 27 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 27 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 27 ) - 5}{2 \cdot 1}

x = \frac{- ( - 27 ) + 5}{2 \cdot 1} : 16

x = \frac{- ( - 27 ) - 5}{2 \cdot 1} : 11

The solutions to the quadratic equation are:

x = 16, x = 11

\frac{m ^{2} - 9}{m - 3}

3 x^{2} - 16 x + 5

3 x^{2} + 15 x + 18

60 + x = 180

1.5 \cdot 1 0^{8}

What are the solutions to the equation x^2-27x+176=0 ?
The solutions to the equation x^2-27x+176=0 are x=16,x=11
Find the zeros of x^2-27x+176=0
The zeros of x^2-27x+176=0 are x=16,x=11